I've read that as a approximate rule you can work out a complimentary Pot/p'up combo by multiplying the Pick-up's DC resistance by 40...
e.g.1:
Vintage Staggered, DC resistance 6.5k
6.5 x 40 = 260
So by this theory 250K Pots will work well...
e.g.2:
'59 Model (neck), DC resistance 7.43k
7.43 x 40 = 297.2
I guess that's why many LPs with traditional PAF's use 300k pots.
What then do you do when you have two different DC res p'ups? For example, I have a JM with a '59 Model (neck), DC resistance 7.43k; and a Duncan Custom (bridge), DC resistance 14.1k.
In theory, the '59 wants 300k pots, and the Custom wants around the 500k-600k region. 300k are gonna muddy up the Custom, and 500k make the '59 too harsh.
Obviously this can be rectified easily in a LP with separate controls, but what about a 1 vol / 1 tone set up?
This is a good question... I hope somebody responds to it.
Rick
Me too! Anyone?
The formula is new to me, though I can well imagine it being factual.....
i actually prefer 59's with 500k's
when distorted, they sound much much meaner
and if it's in the neck position, well for me, i try to get them as bright sounding as possible
I agree with Drew. I like 500k pots for all humbuckers, especiall a 59n. People focus too much on DC resistance. The actual sound comes from AC, you have different magnets that affect tone, the position of the pickup makes a difference because of different string vibration etc.
DC resistance levels are a very simple reference. You need to experiment to really know the results.
- Mar 22 Tue 2011 21:04
How is a Pick-up's DC resistance linked to Pot resistance?
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