Hi:
I have a small data set, and I'm trying to do make some forecasting
functions work, so I use the INTERCEPT() and SLOPE() function in order
to get the line's major elements. BUT! When I double check the
INTERCEPT() and SLOPE() results with the Trendline that Excel has done
using the data set, I get completely different values for the
INTERCEPT!
Any advice out there on how to handle this?? My data set follows
2007 2008 2009
2010
A 195,734.53 211,970.79 229,935.20 249,846.68
B 57,893.65 66,527.44 76,613.14 88,412.49
So the equation from the graph/trendline function: A: y = 18030x
176797; and B:
y = 10164x 46951..
The SLOPE() function is fine and I get matching values, but my
INTERCEPT() values are way off: -35,991,552.05 for A; -20,342,474.73
for B.
Thanks!
The devil is in the details, and you've left out one important detail:
what are you using for known_x? The intercept, of course, is the value
of y when x=0.
If I use quot;2007, 2008, 2009, 2010quot; for known_x, I get the same from
INTERCEPT as your worksheet got. In this case, known_x refers to
quot;years since 1 BCquot; (ie 1 BC is year 0).
If I use quot;1, 2, 3, 4quot; for known_x, I get the same from INTERCEPT as
your chart trendline gave. In this case, known_x refers to quot;years
since 2006quot; (ie 2006 is year 0).
As long as you're consistent in your use of independent variable,
neither is necessarily more correct than the other.--
MrShorty
------------------------------------------------------------------------
MrShorty's Profile: www.excelforum.com/member.php...oamp;userid=22181
View this thread: www.excelforum.com/showthread...hreadid=507461Misha -
If you have a Line chart type, Excel uses 1,2,3,... for the X values of the
trendline.
If you create an XY (Scatter) chart, you should obtain identical results for
the linear trendline and the worksheet functions.
- Mike
www.mikemiddleton.com
quot;Mishaquot; gt; wrote in message oups.com...
gt; Hi:
gt;
gt; I have a small data set, and I'm trying to do make some forecasting
gt; functions work, so I use the INTERCEPT() and SLOPE() function in order
gt; to get the line's major elements. BUT! When I double check the
gt; INTERCEPT() and SLOPE() results with the Trendline that Excel has done
gt; using the data set, I get completely different values for the
gt; INTERCEPT!
gt;
gt; Any advice out there on how to handle this?? My data set follows
gt;
gt; 2007 2008 2009
gt; 2010
gt; A 195,734.53 211,970.79 229,935.20 249,846.68
gt; B 57,893.65 66,527.44 76,613.14 88,412.49
gt;
gt; So the equation from the graph/trendline function: A: y = 18030x
gt; 176797; and B:
gt; y = 10164x 46951..
gt;
gt; The SLOPE() function is fine and I get matching values, but my
gt; INTERCEPT() values are way off: -35,991,552.05 for A; -20,342,474.73
gt; for B.
gt;
gt; Thanks!
gt;
- Nov 18 Sat 2006 20:10
intercept graph vs. function
close
全站熱搜
留言列表
發表留言