sin() seems unable to handle a large number like 1.35 e8? Is anyone aware of
this type of computational limit? Thanks for related information
It seams that the limit is 2^27-1 = 1.34 e8 but I don't know why. To avoid
the error, you can use =sin(mod(1.35 e8, 2 * pi()))
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Rogerio Takejame
Americana - Sao Paulo - Brazilquot;Lafayettequot; wrote:
gt; sin() seems unable to handle a large number like 1.35 e8? Is anyone aware of
gt; this type of computational limit? Thanks for related information
Appreciate your reply. Your solution works pretty well.
quot;Rogerio Takejamequot; wrote:
gt; It seams that the limit is 2^27-1 = 1.34 e8 but I don't know why. To avoid
gt; the error, you can use =sin(mod(1.35 e8, 2 * pi()))
gt;
gt; --
gt; Rogerio Takejame
gt; Americana - Sao Paulo - Brazil
gt;
gt;
gt; quot;Lafayettequot; wrote:
gt;
gt; gt; sin() seems unable to handle a large number like 1.35 e8? Is anyone aware of
gt; gt; this type of computational limit? Thanks for related information
Please, rate this answer
--
Rogerio Takejame
Americana - Sao Paulo - Brazilquot;Lafayettequot; wrote:
gt; Appreciate your reply. Your solution works pretty well.
gt;
gt; quot;Rogerio Takejamequot; wrote:
gt;
gt; gt; It seams that the limit is 2^27-1 = 1.34 e8 but I don't know why. To avoid
gt; gt; the error, you can use =sin(mod(1.35 e8, 2 * pi()))
gt; gt;
gt; gt; --
gt; gt; Rogerio Takejame
gt; gt; Americana - Sao Paulo - Brazil
gt; gt;
gt; gt;
gt; gt; quot;Lafayettequot; wrote:
gt; gt;
gt; gt; gt; sin() seems unable to handle a large number like 1.35 e8? Is anyone aware of
gt; gt; gt; this type of computational limit? Thanks for related information
- Feb 22 Thu 2007 20:35
Limit of number which sin() can handle?
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